out Arguments

Added in ??

Passing Out

Very similar to reference parameters but with two main differences:
1) use the keyword "out"
2) the variable does not have to be assigned before the method is called
What about object types ?
Always ByRef regardless unless you manually clone / serialise the objects first in memory

The out parameter can be used to return the values in the same variable passed as a parameter of the method. Any changes made to the parameter will be reflected in the variable.

public class mathClass 
{ 
    public static int Mehod_TestOut(out int iVal1, out int iVal2) 
    { 
        iVal1 = 10; 
        iVal2 = 20; 
        return 0; 
     } 

    public static void Main() 
    { 
        int i, j; // variable need not be initialized 
        System.Console.WriteLine(Method_TestOut(out i, out j)); 
        System.Console.WriteLine(i); 
        System.Console.WriteLine(j); 
    } 
}