oct |
| oct(x) |
Returns the number converted to a octal string (built-in). |
| arraylist | The name of the array. |
| REMARKS |
| * This is a built-in function. * Convert an integer number to an octal string prefixed with "0o". The result is a valid Python expression. If x is not a Python int object, it has to define an __index__() method that returns an integer. For example: * If you want to convert an integer number to an octal string either with the prefix "0o" or not, you can use either of the following ways. * link to Excel * You can use the octdigits constant * You can use the bin function to * You can use the hex function to * For the Official documentation refer to python.org |
oct(8) #= '0o10'
oct(10) #= '0o12'
oct(-56) #= '-0o70'
%#o' % 10 #= '0o12'
%o' % 10 #= '12'
format(10, '#o') #= '0o12'
format(10, 'o') #= '12')
f'{10:#o}' #= ('0o12'
f'{10:o}' #= '12'
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